What is expand ((n-2)(n-1))/2 ?

The solution to expand ((n-2)(n-1))/2 is (n^2)/2-(3n)/2+1

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expand ((n-2)(n-1))/2

expand

\frac{( n - 2 ) ( n - 1 )}{2}

\frac{n ^{2}}{2} - \frac{3 n}{2} + 1

Solution steps

\frac{( n - 2 ) ( n - 1 )}{2}

Expand

(n - 2) (n - 1) : n^{2} - 3 n + 2

= \frac{n ^{2} - 3 n + 2}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{2} - 3 n + 2}{2} = \frac{n ^{2}}{2} - \frac{3 n}{2} + \frac{2}{2}

= \frac{n ^{2}}{2} - \frac{3 n}{2} + \frac{2}{2}

Apply rule

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{n ^{2}}{2} - \frac{3 n}{2} + 1

\frac{5 ( x - 2 )}{x ^{2}}

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\frac{( x + 3 ) ( x + 2 ) ( x - 5 )}{2 x + 1}

9^{2} - 100

l (e^{x} + e^{- x}) sin (x)

What is expand ((n-2)(n-1))/2 ?
The solution to expand ((n-2)(n-1))/2 is (n^2)/2-(3n)/2+1