What is expand l(e^x+e^{-x})sin(x) ?

The solution to expand l(e^x+e^{-x})sin(x) is le^xsin(x)+le^{-x}sin(x)

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expand l(e^x+e^{-x})sin(x)

expand

l (e^{x} + e^{- x}) sin (x)

l e^{x} sin (x) + l e^{- x} sin (x)

Solution steps

l (e^{x} + e^{- x}) sin (x)

= l sin (x) (e^{x} + e^{- x})

Apply the distributive law:

a (b + c) = ab + a c

a = l sin (x), b = e^{x}, c = e^{- x}

= l sin (x) e^{x} + l sin (x) e^{- x}

= l e^{x} sin (x) + l e^{- x} sin (x)

(\frac{( k ( 3 k + 1 ) )}{2}) + (3 k + 1)

\frac{( - 4 + 5 x ) ^{2}}{16}

2 (- 3 x - 5 y = - 2)

(10 x - 20) e - 0.1 x

\frac{( x - 1 ) ( x - 4 )}{4}

What is expand l(e^x+e^{-x})sin(x) ?
The solution to expand l(e^x+e^{-x})sin(x) is le^xsin(x)+le^{-x}sin(x)