What is expand (((k(3k+1)))/2)+(3k+1) ?

The solution to expand (((k(3k+1)))/2)+(3k+1) is (3k^2)/2+k/2+3k+1

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expand (((k(3k+1)))/2)+(3k+1)

expand

(\frac{( k ( 3 k + 1 ) )}{2}) + (3 k + 1)

\frac{3 k ^{2}}{2} + \frac{k}{2} + 3 k + 1

Solution steps

(\frac{k ( 3 k + 1 )}{2}) + (3 k + 1)

Remove parentheses:

(a) = a

= \frac{k ( 3 k + 1 )}{2} + 3 k + 1

Expand

k (3 k + 1) : 3 k^{2} + k

= \frac{3 k ^{2} + k}{2} + 3 k + 1

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 k ^{2} + k}{2} = \frac{3 k ^{2}}{2} + \frac{k}{2}

= \frac{3 k ^{2}}{2} + \frac{k}{2} + 3 k + 1

\frac{( - 4 + 5 x ) ^{2}}{16}

2 (- 3 x - 5 y = - 2)

(10 x - 20) e - 0.1 x

\frac{( x - 1 ) ( x - 4 )}{4}

(x - 1) e^{x^{2} - 4}

What is expand (((k(3k+1)))/2)+(3k+1) ?
The solution to expand (((k(3k+1)))/2)+(3k+1) is (3k^2)/2+k/2+3k+1