What is expand (x-1)e^{x^2-4} ?

The solution to expand (x-1)e^{x^2-4} is e^{x^2-4}x-e^{x^2-4}

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expand (x-1)e^{x^2-4}

expand

(x - 1) e^{x^{2} - 4}

e^{x^{2} - 4} x - e^{x^{2} - 4}

Solution steps

(x - 1) e^{x^{2} - 4}

= e^{x^{2} - 4} (x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x^{2} - 4}, b = x, c = 1

= e^{x^{2} - 4} x - e^{x^{2} - 4} \cdot 1

= e^{x^{2} - 4} x - 1 \cdot e^{x^{2} - 4}

Multiply:

1 \cdot e^{x^{2} - 4} = e^{x^{2} - 4}

= e^{x^{2} - 4} x - e^{x^{2} - 4}

\frac{( x - 1 )}{( x ( x + 3 ) )}

\frac{10 ( 3 - 6 )}{3}

(x - y - 1) d x + (4 y + x - 1) d y

\frac{8 x + 4}{( 1 - x ) ( x + 2 )}

- sin (π t) (u (t - 1))

What is expand (x-1)e^{x^2-4} ?
The solution to expand (x-1)e^{x^2-4} is e^{x^2-4}x-e^{x^2-4}