What is expand pi^{e^0}-arccos(0) ?

The solution to expand pi^{e^0}-arccos(0) is pi-pi/2

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expand pi^{e^0}-arccos(0)

expand

π^{e^{0}} - arccos (0)

π - \frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

π^{e^{0}} - arccos (0)

Apply rule

a^{0} = 1, a \neq = 0

e^{0} = 1

= π^{1} - arccos (0)

Apply rule

a^{1} = a

= π - arccos (0)

Use the following trivial identity:

arccos (0) = \frac{π}{2}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= π - \frac{π}{2}

(2 - j^{2})^{8}

w + 14 w - 6 w

520

(3 x + 1) d x

\frac{- 2 x ^{2} + 4 x - 1}{x ( x - 1 )}

What is expand pi^{e^0}-arccos(0) ?
The solution to expand pi^{e^0}-arccos(0) is pi-pi/2