What are the solutions to the equation 4x^2+77=-36x ?

The solutions to the equation 4x^2+77=-36x are x=-7/2 ,x=-11/2

Find the zeros of 4x^2+77=-36x

The zeros of 4x^2+77=-36x are x=-7/2 ,x=-11/2

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4 x^{2} + 77 = - 36 x

x = - \frac{7}{2}, x = - \frac{11}{2}

Solution steps

4 x^{2} + 77 = - 36 x

Move

36 x

to the left side

4 x^{2} + 77 + 36 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 36 x + 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 4 \cdot 77}{2 \cdot 4}

3 6^{2} - 4 \cdot 4 \cdot 77 = 8

x_{1, 2} = \frac{- 36 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 36 + 8}{2 \cdot 4}, x_{2} = \frac{- 36 - 8}{2 \cdot 4}

x = \frac{- 36 + 8}{2 \cdot 4} : - \frac{7}{2}

x = \frac{- 36 - 8}{2 \cdot 4} : - \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{7}{2}, x = - \frac{11}{2}

(6 x + 2)^{2} + 4 = 28

\frac{4 ^{n}}{2 ^{m}}

125 a^{3} - 64

80

\frac{8}{4 + 3 i}

What are the solutions to the equation 4x^2+77=-36x ?
The solutions to the equation 4x^2+77=-36x are x=-7/2 ,x=-11/2
Find the zeros of 4x^2+77=-36x
The zeros of 4x^2+77=-36x are x=-7/2 ,x=-11/2