What is expand x^3Δ(Δ^2+3Δ+3) ?

The solution to expand x^3Δ(Δ^2+3Δ+3) is Δ^3x^3+3Δ^2x^3+3Δx^3

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expand x^3Δ(Δ^2+3Δ+3)

expand

x^{3} Δ (Δ^{2} + 3Δ + 3)

Δ^{3} x^{3} + 3 Δ^{2} x^{3} + 3Δ x^{3}

Solution steps

x^{3} Δ (Δ^{2} + 3Δ + 3)

= Δ (Δ^{2} + 3Δ + 3) x^{3}

Distribute parentheses

= x^{3} Δ Δ^{2} + x^{3} Δ3Δ + x^{3} Δ3

= Δ^{2} Δ x^{3} + 3ΔΔ x^{3} + 3Δ x^{3}

Simplify

Δ^{2} Δ x^{3} + 3ΔΔ x^{3} + 3Δ x^{3} : Δ^{3} x^{3} + 3 Δ^{2} x^{3} + 3Δ x^{3}

= Δ^{3} x^{3} + 3 Δ^{2} x^{3} + 3Δ x^{3}

p^{1} (- 2, - 3)

\frac{2 x ^{2}}{( 5 x + 1 ) ( x - 2 )}

sec (t) (5 sec (t) + 3 tan (t)) d t

A (12, 7) B (- 3, 5) C (10, - 4)

\frac{3 k ( k + 1 )}{2} + (k + 1)

What is expand x^3Δ(Δ^2+3Δ+3) ?
The solution to expand x^3Δ(Δ^2+3Δ+3) is Δ^3x^3+3Δ^2x^3+3Δx^3