What is expand 2\H(t-2)(t-2)-t+4\H(t) ?

The solution to expand 2\H(t-2)(t-2)-t+4\H(t) is 2t\H(t-2)-4\H(t-2)-t+4\H(t)

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expand 2\H(t-2)(t-2)-t+4\H(t)

expand

2 H (t - 2) (t - 2) - t + 4 H (t)

2 t H (t - 2) - 4 H (t - 2) - t + 4 H (t)

Solution steps

2 H (t - 2) (t - 2) - t + 4 H (t)

Expand

2 H (t - 2) (t - 2) : 2 t H (t - 2) - 4 H (t - 2)

= 2 t H (t - 2) - 4 H (t - 2) - t + 4 H (t)

\frac{10 ( s + 1 )}{s ^{2} + s + 10}

\frac{4 x + 5}{( x - 2 ) ^{3} ( x + 3 )}

\frac{3 a ( a - 2 b ) ^{2}}{2 b ^{3}}

α (c α, a α + b α + c α, 4 a α + 2 b α + c α)

- \frac{8 s + 25}{( s + 4 ) ^{2}}

What is expand 2\H(t-2)(t-2)-t+4\H(t) ?
The solution to expand 2\H(t-2)(t-2)-t+4\H(t) is 2t\H(t-2)-4\H(t-2)-t+4\H(t)