What is expand ((y-6)(y+3))/((2y+3)(y+1)) ?

The solution to expand ((y-6)(y+3))/((2y+3)(y+1)) is (y^2-3y-18)/(2y^2+5y+3)

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expand ((y-6)(y+3))/((2y+3)(y+1))

expand

\frac{( y - 6 ) ( y + 3 )}{( 2 y + 3 ) ( y + 1 )}

\frac{y ^{2} - 3 y - 18}{2 y ^{2} + 5 y + 3}

Solution steps

\frac{( y - 6 ) ( y + 3 )}{( 2 y + 3 ) ( y + 1 )}

Expand

(2 y + 3) (y + 1) : 2 y^{2} + 5 y + 3

= \frac{( y - 6 ) ( y + 3 )}{2 y ^{2} + 5 y + 3}

Expand

(y - 6) (y + 3) : y^{2} - 3 y - 18

= \frac{y ^{2} - 3 y - 18}{2 y ^{2} + 5 y + 3}

\frac{u - 1}{u}

\frac{d}{d x} ((x) (x^{2} + y^{2}))

- 8 (4 n - 1 = 2 (9 - 3 n))

(4 n^{2} + 2 n - 1) (2 n - 1)!

What is expand ((y-6)(y+3))/((2y+3)(y+1)) ?
The solution to expand ((y-6)(y+3))/((2y+3)(y+1)) is (y^2-3y-18)/(2y^2+5y+3)