What is expand (3(144+9sqrt(6)))/(125) ?

The solution to expand (3(144+9sqrt(6)))/(125) is 432/125+(27sqrt(6))/(125)

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expand (3(144+9sqrt(6)))/(125)

expand

\frac{3 ( 144 + 9 6 )}{125}

\frac{432}{125} + \frac{27 6}{125}

Decimal Notation

3.98508 \dots

Solution steps

\frac{3 ( 144 + 9 6 )}{125}

Expand

3 (144 + 96) : 432 + 276

= \frac{432 + 27 6}{125}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{432 + 27 6}{125} = \frac{432}{125} + \frac{27 6}{125}

= \frac{432}{125} + \frac{27 6}{125}

(x + 1) d y - [3 y]

\frac{5 ( 3 + 2 x )}{2 ( 5 - 4 x )}

\frac{x - 3 ( 2 y - z )}{2 x y}

3 (2 z - 10 = - 12)

cos (2) (x + \frac{π}{8})

What is expand (3(144+9sqrt(6)))/(125) ?
The solution to expand (3(144+9sqrt(6)))/(125) is 432/125+(27sqrt(6))/(125)