What is expand s/((s+3)(s+4)(s+1)) ?

The solution to expand s/((s+3)(s+4)(s+1)) is s/(s^3+8s^2+19s+12)

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expand s/((s+3)(s+4)(s+1))

expand

\frac{s}{( s + 3 ) ( s + 4 ) ( s + 1 )}

\frac{s}{s ^{3} + 8 s ^{2} + 19 s + 12}

Solution steps

\frac{s}{( s + 3 ) ( s + 4 ) ( s + 1 )}

Expand

(s + 3) (s + 4) (s + 1) : s^{3} + 8 s^{2} + 19 s + 12

= \frac{s}{s ^{3} + 8 s ^{2} + 19 s + 12}

4 (1 - e^{- \frac{9.8 x}{4}})

(3 c - 4 e - 2 b) (- 3 c - 4 d + b)

sec (a) (2, - 1)

(2 x^{2} - 5) e^{x^{2}}

\frac{e ^{- 3 s}}{s ^{2} ( s ^{2} + 4 )}

What is expand s/((s+3)(s+4)(s+1)) ?
The solution to expand s/((s+3)(s+4)(s+1)) is s/(s^3+8s^2+19s+12)