What are the solutions to the equation 36x^2-25=0 ?

The solutions to the equation 36x^2-25=0 are x= 5/6 ,x=-5/6

Find the zeros of 36x^2-25=0

The zeros of 36x^2-25=0 are x= 5/6 ,x=-5/6

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36 x^{2} - 25 = 0

x = \frac{5}{6}, x = - \frac{5}{6}

Solution steps

36 x^{2} - 25 = 0

Move

25

to the right side

36 x^{2} = 25

Divide both sides by

36

x^{2} = \frac{25}{36}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{36}, x = - \frac{25}{36}

\frac{25}{36} = \frac{5}{6}

- \frac{25}{36} = - \frac{5}{6}

x = \frac{5}{6}, x = - \frac{5}{6}

\frac{( \frac{3}{2} ) ^{6}}{( \frac{3}{5} ) ^{6}} - ((\frac{5}{2})^{2})^{3}

x^{2} - 4 x - 45 \geq 0

t^{2} = 7 t

\frac{3}{5} (x + 2) = x - 4

(2 - 3 i)^{3}

What are the solutions to the equation 36x^2-25=0 ?
The solutions to the equation 36x^2-25=0 are x= 5/6 ,x=-5/6
Find the zeros of 36x^2-25=0
The zeros of 36x^2-25=0 are x= 5/6 ,x=-5/6