What are the solutions to the equation t^2=7t ?

The solutions to the equation t^2=7t are t=7,t=0

Find the zeros of t^2=7t

The zeros of t^2=7t are t=7,t=0

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t^{2} = 7 t

t = 7, t = 0

Solution steps

t^{2} = 7 t

Move

7 t

to the left side

t^{2} - 7 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 0 = 7

t_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 1}, t_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 1}

t = \frac{- ( - 7 ) + 7}{2 \cdot 1} : 7

t = \frac{- ( - 7 ) - 7}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 7, t = 0

\frac{3}{5} (x + 2) = x - 4

(2 - 3 i)^{3}

(\frac{5 ^{2}}{5 ^{- 1}})^{3}

x^{2} + 12 x = x - 24

\frac{a ^{3}}{a ^{2}}

What are the solutions to the equation t^2=7t ?
The solutions to the equation t^2=7t are t=7,t=0
Find the zeros of t^2=7t
The zeros of t^2=7t are t=7,t=0