What is (1/x \circ 7-x)(x) ?

The solution to (1/x \circ 7-x)(x) is -x^2+7\circ

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simplify (1/x \circ 7-x)(x)

simplify

(\frac{1}{x} \circ 7 - x) (x)

- x^{2} + 7 \circ

Solution steps

(\frac{1}{x} \circ 7 - x) (x)

Remove parentheses:

(a) = a

= (\frac{1}{x} \circ 7 - x) x

\frac{1}{x} \circ 7 = \frac{7 \circ}{x}

= x (- x + \frac{7 \circ}{x})

= x (\frac{7 \circ}{x} - x)

Apply the distributive law:

a (b - c) = ab - a c

a = x, b = \frac{7 \circ}{x}, c = x

= x \frac{7 \circ}{x} - xx

= \frac{7 \circ}{x} x - xx

Simplify

\frac{7 \circ}{x} x - xx : 7 \circ - x^{2}

= 7 \circ - x^{2}

Rewrite in standard form

= - x^{2} + 7 \circ

\frac{5}{( x + 1 ) ^{2}}

- 2 cos (2 (x - \frac{π}{4})) - 3

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