What is expand (f(x+h)-9x-9x^2)/h ?

The solution to expand (f(x+h)-9x-9x^2)/h is (fx)/h+f-(9x)/h-(9x^2)/h

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expand (f(x+h)-9x-9x^2)/h

expand

\frac{f ( x + h ) - 9 x - 9 x ^{2}}{h}

\frac{f x}{h} + f - \frac{9 x}{h} - \frac{9 x ^{2}}{h}

Solution steps

\frac{f ( x + h ) - 9 x - 9 x ^{2}}{h}

Expand

f (x + h) - 9 x - 9 x^{2} : f x + f h - 9 x - 9 x^{2}

= \frac{f x + f h - 9 x - 9 x ^{2}}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{f x + f h - 9 x - 9 x ^{2}}{h} = \frac{f x}{h} + \frac{f h}{h} - \frac{9 x}{h} - \frac{9 x ^{2}}{h}

= \frac{f x}{h} + \frac{f h}{h} - \frac{9 x}{h} - \frac{9 x ^{2}}{h}

Cancel

\frac{f h}{h} : f

= \frac{f x}{h} + f - \frac{9 x}{h} - \frac{9 x ^{2}}{h}

\frac{5}{6 ( a + b + c )}

f (x^{2} - 9) \circ g (x^{2} + 3 x)

(x^{2} y^{2} + x^{2} + y^{2} + 1) d y

\frac{a}{b} (2 x - 12 = \frac{c}{d})

\frac{3 π ( 2 + 2 )}{32}

What is expand (f(x+h)-9x-9x^2)/h ?
The solution to expand (f(x+h)-9x-9x^2)/h is (fx)/h+f-(9x)/h-(9x^2)/h