What is expand (f\circ g)(x+2)(2x-1) ?

The solution to expand (f\circ g)(x+2)(2x-1) is 2\circ fgx^2+3\circ fgx-2\circ fg

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expand (f\circ g)(x+2)(2x-1)

expand

(f \circ g) (x + 2) (2 x - 1)

2 \circ f g x^{2} + 3 \circ f gx - 2 \circ f g

Solution steps

(f \circ g) (x + 2) (2 x - 1)

= (\circ f g) (x + 2) (2 x - 1)

Expand

(x + 2) (2 x - 1) : 2 x^{2} + 3 x - 2

= (f \circ g) (2 x^{2} + 3 x - 2)

Expand

(f \circ g) (2 x^{2} + 3 x - 2) : 2 \circ f g x^{2} + 3 \circ f gx - 2 \circ f g

= 2 \circ f g x^{2} + 3 \circ f gx - 2 \circ f g

\frac{1}{( 2 + sin ( θ ) ) ^{4}}

(1 - ln (x)) d x + (1 - ln (y)) d y

\frac{( 3 x ^{2} - x ) ^{3}}{3}

\frac{1}{s C ( L s + R ) + 1}

\frac{n ( 11 - n )}{2}

What is expand (f\circ g)(x+2)(2x-1) ?
The solution to expand (f\circ g)(x+2)(2x-1) is 2\circ fgx^2+3\circ fgx-2\circ fg