What is expand 15(3x-1)-7(x-1=2(1+9x)) ?

The solution to expand 15(3x-1)-7(x-1=2(1+9x)) is 38x-8=2+18x

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expand 15(3x-1)-7(x-1=2(1+9x))

expand

15 (3 x - 1) - 7 (x - 1 = 2 (1 + 9 x))

38 x - 8 = 2 + 18 x

Solution steps

15 (3 x - 1) - 7 (x - 1 = 2 (1 + 9 x))

= 15 (3 x - 1) - 7 (x - 1 \cdot 2 = (1 + 9 x))

Expand

15 (3 x - 1) : 45 x - 15

= 45 x - 15 - 7 (x - 1 = 2 (1 + 9 x))

Expand

- 7 (x - 1 = 2 (1 + 9 x)) : - 7 x + 7 = 2 + 18 x

45 x - 15 - 7 x + 7 = 2 + 18 x

Expand

45 x - 15 - 7 x + 7 : 38 x - 8

38 x - 8 = 2 + 18 x

\frac{n ( n - 1 ) ( n + 1 )}{3}

(x + h)^{(2)} - 3

\frac{n T}{s ( R ( M + n ^{2} J ) s + TB )}

10 x - (2 x + 9 = - 3 (15 - 4 x))

- \frac{4 ( 11 + 341 )}{11}

What is expand 15(3x-1)-7(x-1=2(1+9x)) ?
The solution to expand 15(3x-1)-7(x-1=2(1+9x)) is 38x-8=2+18x