What is expand ((3x-2)(x+1))/(x+2) ?

The solution to expand ((3x-2)(x+1))/(x+2) is (3x^2+x-2)/(x+2)

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expand ((3x-2)(x+1))/(x+2)

expand

\frac{( 3 x - 2 ) ( x + 1 )}{x + 2}

\frac{3 x ^{2} + x - 2}{x + 2}

Solution steps

\frac{( 3 x - 2 ) ( x + 1 )}{x + 2}

Expand

(3 x - 2) (x + 1) : 3 x^{2} + x - 2

= \frac{3 x ^{2} + x - 2}{x + 2}

- x^{2} e^{- x} - 2 e^{- x} (x + 1) + 2

\frac{( ( n + 1 ) ( n + 2 ) ( 2 n + 3 ) )}{6}

2 h (x) - (6 x - 1 - 5 = - 1)

2 (e^{x} - e^{- x}) (e^{x} + e^{- x})

\frac{3 ( 5 x - 6 )}{2}

What is expand ((3x-2)(x+1))/(x+2) ?
The solution to expand ((3x-2)(x+1))/(x+2) is (3x^2+x-2)/(x+2)