What is expand 2(x-3= 1/2 (4x-12)) ?

The solution to expand 2(x-3= 1/2 (4x-12)) is 2x-6=2x-6

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expand 2(x-3= 1/2 (4x-12))

expand

2 (x - 3 = \frac{1}{2} (4 x - 12))

2 x - 6 = 2 x - 6

Solution steps

2 (x - 3 = \frac{1}{2} (4 x - 12))

= 2 (x - 3 \cdot \frac{1}{2} = (4 x - 12))

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = x, c = 3 = \frac{1}{2} (4 x - 12)

2 x - 2 \cdot 3 = \frac{1}{2} (4 x - 12)

Simplify

2 x - 2 \cdot 3 = \frac{1}{2} (4 x - 12) : 2 x - 6 = 2 x - 6

2 x - 6 = 2 x - 6

(1, - 1, 1) x (1, 1, - 1)

f (x) = (x + 2)^{24}

\frac{3 ( x ^{2} - 5 x ) + 2}{2}

2 (x^{2} - 3 x + 8)^{2}

\frac{3}{( 3 x + c ) ^{3}}

What is expand 2(x-3= 1/2 (4x-12)) ?
The solution to expand 2(x-3= 1/2 (4x-12)) is 2x-6=2x-6