What are the solutions to the equation -x^2+4x=9 ?

The solutions to the equation -x^2+4x=9 are x=2-sqrt(5)i,x=2+sqrt(5)i

Find the zeros of -x^2+4x=9

The zeros of -x^2+4x=9 are x=2-sqrt(5)i,x=2+sqrt(5)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 4 x = 9

x = 2 - 5 i, x = 2 + 5 i

Solution steps

- x^{2} + 4 x = 9

Move

9

to the left side

- x^{2} + 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 9 )}{2 ( - 1 )}

Simplify

4^{2} - 4 (- 1) (- 9) : 25 i

x_{1, 2} = \frac{- 4 \pm 2 5 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 5 i}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 5 i}{2 ( - 1 )}

x = \frac{- 4 + 2 5 i}{2 ( - 1 )} : 2 - 5 i

x = \frac{- 4 - 2 5 i}{2 ( - 1 )} : 2 + 5 i

The solutions to the quadratic equation are:

x = 2 - 5 i, x = 2 + 5 i

∣ x - 2 ∣ = ∣ x - 4 ∣

\frac{x - 9}{3} = - 7

- g - 24 = - 17

2 x^{2} - 7 x - 4 = 0

e^{- l n (t)}

What are the solutions to the equation -x^2+4x=9 ?
The solutions to the equation -x^2+4x=9 are x=2-sqrt(5)i,x=2+sqrt(5)i
Find the zeros of -x^2+4x=9
The zeros of -x^2+4x=9 are x=2-sqrt(5)i,x=2+sqrt(5)i