What is expand ((12-3x)^2)/4 ?

The solution to expand ((12-3x)^2)/4 is (9x^2)/4-18x+36

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expand ((12-3x)^2)/4

expand

\frac{( 12 - 3 x ) ^{2}}{4}

\frac{9 x ^{2}}{4} - 18 x + 36

Solution steps

\frac{( 12 - 3 x ) ^{2}}{4}

(12 - 3 x)^{2} = 144 - 72 x + 9 x^{2}

= \frac{144 - 72 x + 9 x ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{144 - 72 x + 9 x ^{2}}{4} = \frac{144}{4} - \frac{72 x}{4} + \frac{9 x ^{2}}{4}

= \frac{144}{4} - \frac{72 x}{4} + \frac{9 x ^{2}}{4}

Divide the numbers:

\frac{144}{4} = 36

= 36 - \frac{72 x}{4} + \frac{9 x ^{2}}{4}

Divide the numbers:

\frac{72}{4} = 18

= 36 - 18 x + \frac{9 x ^{2}}{4}

Rewrite in standard form

= \frac{9 x ^{2}}{4} - 18 x + 36

(a ce + b df)^{4}

9 x - 3 x + 5 (1 + 2 x = 7 x + 3 (x - 4))

2 ((5 y + 9) (2 y - 2))

\frac{1}{lo g _{10} ( x ) ( 8 + x )}

t^{2} H (t - 4) d t

What is expand ((12-3x)^2)/4 ?
The solution to expand ((12-3x)^2)/4 is (9x^2)/4-18x+36