What is expand 9x-3x+5(1+2x=7x+3(x-4)) ?

The solution to expand 9x-3x+5(1+2x=7x+3(x-4)) is 16x+5=22x-60

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expand 9x-3x+5(1+2x=7x+3(x-4))

expand

9 x - 3 x + 5 (1 + 2 x = 7 x + 3 (x - 4))

16 x + 5 = 22 x - 60

Solution steps

9 x - 3 x + 5 (1 + 2 x = 7 x + 3 (x - 4))

= 9 x - 3 x + 5 (1 + 2 \cdot 7 = xx + 3 (x - 4))

Expand

5 (1 + 2 x = 7 x + 3 (x - 4)) : 5 + 10 x = 22 x - 60

9 x - 3 x + 5 + 10 x = 22 x - 60

Expand

9 x - 3 x + 5 + 10 x : 16 x + 5

16 x + 5 = 22 x - 60

2 ((5 y + 9) (2 y - 2))

\frac{1}{lo g _{10} ( x ) ( 8 + x )}

t^{2} H (t - 4) d t

x^{(a - b) (a^{2} + ab + b^{2})}

\frac{( x + 3 ) ( x - 2 )}{( x + 1 ) ( x - 4 )}

What is expand 9x-3x+5(1+2x=7x+3(x-4)) ?
The solution to expand 9x-3x+5(1+2x=7x+3(x-4)) is 16x+5=22x-60