What is expand 6(((x-1))/3)^2 ?

The solution to expand 6(((x-1))/3)^2 is (2x^2)/3-(4x)/3+2/3

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expand 6(((x-1))/3)^2

expand

6 (\frac{( x - 1 )}{3})^{2}

\frac{2 x ^{2}}{3} - \frac{4 x}{3} + \frac{2}{3}

Solution steps

6 (\frac{x - 1}{3})^{2}

(\frac{x - 1}{3})^{2} = \frac{x ^{2} - 2 x + 1}{3 ^{2}}

= 6 \cdot \frac{x ^{2} - 2 x + 1}{3 ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{2} - 2 x + 1 ) \cdot 6}{3 ^{2}}

Factor

6 : 2 \cdot 3

= \frac{2 \cdot 3 ( x ^{2} - 2 x + 1 )}{3 ^{2}}

Cancel the common factor:

3

= \frac{2 ( x ^{2} - 2 x + 1 )}{3}

Expand

2 (x^{2} - 2 x + 1) : 2 x^{2} - 4 x + 2

= \frac{2 x ^{2} - 4 x + 2}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} - 4 x + 2}{3} = \frac{2 x ^{2}}{3} - \frac{4 x}{3} + \frac{2}{3}

= \frac{2 x ^{2}}{3} - \frac{4 x}{3} + \frac{2}{3}

- \frac{3 ( 35 - 5 )}{10}

C (2, - 1) 4

\frac{( - 4 + x ) ^{2}}{16}

6 (x - (2 x + 3) = 8 - 5 x)

(x + 7) ((x + Δ x) + 7)

What is expand 6(((x-1))/3)^2 ?
The solution to expand 6(((x-1))/3)^2 is (2x^2)/3-(4x)/3+2/3