What is expand 6(x-(2x+3)=8-5x) ?

The solution to expand 6(x-(2x+3)=8-5x) is -6x-18=8-30x

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expand 6(x-(2x+3)=8-5x)

expand

6 (x - (2 x + 3) = 8 - 5 x)

- 6 x - 18 = 8 - 30 x

Solution steps

6 (x - (2 x + 3) = 8 - 5 x)

= 6 (x - 8 = (2 x + 3) - 5 x)

Distribute parentheses

= 6 x + 6 (- (2 x + 3) = 8) + 6 (- 5 x)

Apply minus-plus rules

+ (- a) = - a

6 x - 6 (2 x + 3) = 8 - 6 \cdot 5 x

Simplify

6 x - 6 (2 x + 3) = 8 - 6 \cdot 5 x : - 6 x - 18 = 8 - 30 x

- 6 x - 18 = 8 - 30 x

(x + 7) ((x + Δ x) + 7)

\frac{( - 5 x + 55 ) ( 11 - x )}{2}

\frac{1}{( s + 10 ) ( s ^{2} + 4 s + 10 )}

(3 + 2 i) \cdot [6 + 3 i, 0 + 0 i, 5 + 1 i, 4]

lo g_{8} (27)

What is expand 6(x-(2x+3)=8-5x) ?
The solution to expand 6(x-(2x+3)=8-5x) is -6x-18=8-30x