What are the solutions to the equation x^2-5x+3=0 ?

The solutions to the equation x^2-5x+3=0 are x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2

Find the zeros of x^2-5x+3=0

The zeros of x^2-5x+3=0 are x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2

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x^{2} - 5 x + 3 = 0

x = \frac{5 + 13}{2}, x = \frac{5 - 13}{2}

Decimal Notation

x = 4.30277 \dots, x = 0.69722 \dots

Solution steps

x^{2} - 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 3 = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

x = \frac{- ( - 5 ) + 13}{2 \cdot 1} : \frac{5 + 13}{2}

x = \frac{- ( - 5 ) - 13}{2 \cdot 1} : \frac{5 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 13}{2}, x = \frac{5 - 13}{2}

x \leq 4 and x > - 2

- \frac{1}{4} - 1

(2 x + 9)^{2} - 1 = 0

x d y - y d x - x^{2} - y^{2} d x

x + 3 + 3

What are the solutions to the equation x^2-5x+3=0 ?
The solutions to the equation x^2-5x+3=0 are x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2
Find the zeros of x^2-5x+3=0
The zeros of x^2-5x+3=0 are x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2