What is expand 2^{x-2}(1-xln(2)) ?

The solution to expand 2^{x-2}(1-xln(2)) is 2^{x-2}-ln(2)*2^{x-2}x

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expand 2^{x-2}(1-xln(2))

expand

2^{x - 2} (1 - x ln (2))

2^{x - 2} - ln (2) \cdot 2^{x - 2} x

Solution steps

2^{x - 2} (1 - x ln (2))

= 2^{x - 2} (1 - ln (2) x)

Apply the distributive law:

a (b - c) = ab - a c

a = 2^{x - 2}, b = 1, c = x ln (2)

= 2^{x - 2} \cdot 1 - 2^{x - 2} x ln (2)

= 1 \cdot 2^{x - 2} - ln (2) \cdot 2^{x - 2} x

Multiply:

1 \cdot 2^{x - 2} = 2^{x - 2}

= 2^{x - 2} - ln (2) \cdot 2^{x - 2} x

e^{3 t - 18} h (t - 6)

- 3 (e - 2)

(e^{x} - e^{- x})^{2} e^{x}

R (a)^{1 - \frac{R}{k}}

\frac{a ( 1 - r )}{r + 1}

What is expand 2^{x-2}(1-xln(2)) ?
The solution to expand 2^{x-2}(1-xln(2)) is 2^{x-2}-ln(2)*2^{x-2}x