What is expand e^{3t-18}h(t-6) ?

The solution to expand e^{3t-18}h(t-6) is e^{3t-18}th-6e^{3t-18}h

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expand e^{3t-18}h(t-6)

expand

e^{3 t - 18} h (t - 6)

e^{3 t - 18} t h - 6 e^{3 t - 18} h

Solution steps

e^{3 t - 18} h (t - 6)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{3 t - 18} h, b = t, c = 6

= e^{3 t - 18} h t - e^{3 t - 18} h \cdot 6

= e^{3 t - 18} t h - 6 e^{3 t - 18} h

- 3 (e - 2)

(e^{x} - e^{- x})^{2} e^{x}

R (a)^{1 - \frac{R}{k}}

\frac{a ( 1 - r )}{r + 1}

3 (2 - i) (2 + 3 i)^{i}

What is expand e^{3t-18}h(t-6) ?
The solution to expand e^{3t-18}h(t-6) is e^{3t-18}th-6e^{3t-18}h