What is expand 3(2-i)(2+3i)^i ?

The solution to expand 3(2-i)(2+3i)^i is 6(2+3i)^i-3i(2+3i)^i

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expand 3(2-i)(2+3i)^i

expand

3 (2 - i) (2 + 3 i)^{i}

6 (2 + 3 i)^{i} - 3 i (2 + 3 i)^{i}

Solution steps

3 (2 - i) (2 + 3 i)^{i}

Apply the distributive law:

a (b - c) = ab - a c

a = 3 (2 + 3 i)^{i}, b = 2, c = i

= 3 (2 + 3 i)^{i} \cdot 2 - 3 (2 + 3 i)^{i} i

= 3 \cdot 2 (2 + 3 i)^{i} - 3 i (2 + 3 i)^{i}

Multiply the numbers:

3 \cdot 2 = 6

= 6 (2 + 3 i)^{i} - 3 i (2 + 3 i)^{i}

1 + \frac{1}{2}

(2 y^{3} - 2 y) 3^{^{'}}

\frac{n + 2}{( n + 3 ) ^{2}}

(7 x + 8 y = 29, 0) (5 x + 11 y = 2600)

\frac{( 1 + x ) ^{2}}{100}

What is expand 3(2-i)(2+3i)^i ?
The solution to expand 3(2-i)(2+3i)^i is 6(2+3i)^i-3i(2+3i)^i