What are the solutions to the equation 48=3(x+2)^2 ?

The solutions to the equation 48=3(x+2)^2 are x=2,x=-6

Find the zeros of 48=3(x+2)^2

The zeros of 48=3(x+2)^2 are x=2,x=-6

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48 = 3 (x + 2)^{2}

x = 2, x = - 6

Solution steps

48 = 3 (x + 2)^{2}

Switch sides

3 (x + 2)^{2} = 48

Divide both sides by

3

(x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 16 : x = 2

Solve

x + 2 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

170.5 \geq x 15.5

3 x + \frac{1}{2} - 2 < 5

6 d - 211 = 2 d - 213

x^{2} - 6 x = 20

\frac{1}{2} \cdot \frac{2}{3}

What are the solutions to the equation 48=3(x+2)^2 ?
The solutions to the equation 48=3(x+2)^2 are x=2,x=-6
Find the zeros of 48=3(x+2)^2
The zeros of 48=3(x+2)^2 are x=2,x=-6