What is expand ((2x+1)(3x+1))/6 ?

The solution to expand ((2x+1)(3x+1))/6 is x^2+(5x)/6+1/6

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expand ((2x+1)(3x+1))/6

expand

\frac{( 2 x + 1 ) ( 3 x + 1 )}{6}

x^{2} + \frac{5 x}{6} + \frac{1}{6}

Solution steps

\frac{( 2 x + 1 ) ( 3 x + 1 )}{6}

Expand

(2 x + 1) (3 x + 1) : 6 x^{2} + 5 x + 1

= \frac{6 x ^{2} + 5 x + 1}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + 5 x + 1}{6} = \frac{6 x ^{2}}{6} + \frac{5 x}{6} + \frac{1}{6}

= \frac{6 x ^{2}}{6} + \frac{5 x}{6} + \frac{1}{6}

Divide the numbers:

\frac{6}{6} = 1

= x^{2} + \frac{5 x}{6} + \frac{1}{6}

\frac{x ^{2} - 1}{3 ( 2 x - 1 )}

2 a C e^{a t} (1 + b C e^{a t})

\frac{2}{( 1.96 ) ^{4}}

(24 x y - 6 x^{2} y - 4 x y^{2}) d x

e^{x} \cdot (1 + e^{- x})^{2}

What is expand ((2x+1)(3x+1))/6 ?
The solution to expand ((2x+1)(3x+1))/6 is x^2+(5x)/6+1/6