What is expand 1/((x-3)(x^3(y))) ?

The solution to expand 1/((x-3)(x^3(y))) is 1/(x^4y-3x^3y)

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expand 1/((x-3)(x^3(y)))

expand

\frac{1}{( x - 3 ) ( x ^{3} ( y ) )}

\frac{1}{x ^{4} y - 3 x ^{3} y}

Solution steps

\frac{1}{( x - 3 ) ( x ^{3} ( y ) )}

Remove parentheses:

(a) = a

= \frac{1}{( x - 3 ) x ^{3} y}

Expand

(x - 3) x^{3} y : x^{4} y - 3 x^{3} y

= \frac{1}{x ^{4} y - 3 x ^{3} y}

\frac{2 x}{( 16 - x ^{2} ) ^{2}}

\frac{( n + 1 ) ( 4 n - 1 )}{( 4 n + 3 ) n}

\frac{1}{s ^{2} ( s ^{2} + 16 )}

(ln (y) = x - 2) e

(- 4 x) (8 x) - 1 - x^{2} - 4 x

What is expand 1/((x-3)(x^3(y))) ?
The solution to expand 1/((x-3)(x^3(y))) is 1/(x^4y-3x^3y)