What is expand 2pi((x+1)(sin(x))+cos(x)) ?

The solution to expand 2pi((x+1)(sin(x))+cos(x)) is 2pixsin(x)+2pisin(x)+2picos(x)

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expand 2pi((x+1)(sin(x))+cos(x))

expand

2 π ((x + 1) (sin (x)) + cos (x))

2 π x sin (x) + 2 π sin (x) + 2 π cos (x)

Solution steps

2 π ((x + 1) (sin (x)) + cos (x))

= 2 π ((sin (x)) (x + 1) + cos (x))

Apply the distributive law:

a (b + c) = ab + a c

a = 2 π, b = (x + 1) (sin (x)), c = cos (x)

= 2 π (x + 1) (sin (x)) + 2 π cos (x)

= 2 π (sin (x)) (x + 1) + 2 π cos (x)

Simplify

2 π (sin (x)) (x + 1) + 2 π cos (x) : 2 π x sin (x) + 2 π sin (x) + 2 π cos (x)

= 2 π x sin (x) + 2 π sin (x) + 2 π cos (x)

\frac{1}{s ^{2} ( x + 4 ) ^{2}}

e^{2 x} (2 + e^{x} + x e^{x})

(2 x^{2} - 3 x - 2) \pm (4 x^{2} + 5 x + 3)

(t + 2)^{2} e^{t}

3 ((2, 0, - 1) - 2 (1, 2, 3))

What is expand 2pi((x+1)(sin(x))+cos(x)) ?
The solution to expand 2pi((x+1)(sin(x))+cos(x)) is 2pixsin(x)+2pisin(x)+2picos(x)