What is expand (2x^2-3x-2)\pm (4x^2+5x+3) ?

The solution to expand (2x^2-3x-2)\pm (4x^2+5x+3) is 8\pm x^4-2\pm x^3-17\pm x^2-19\pm x-6\pm

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expand (2x^2-3x-2)\pm (4x^2+5x+3)

expand

(2 x^{2} - 3 x - 2) \pm (4 x^{2} + 5 x + 3)

8 \pm x^{4} - 2 \pm x^{3} - 17 \pm x^{2} - 19 \pm x - 6 \pm

Solution steps

(2 x^{2} - 3 x - 2) \pm (4 x^{2} + 5 x + 3)

= \pm (2 x^{2} - 3 x - 2) (4 x^{2} + 5 x + 3)

Expand

(2 x^{2} - 3 x - 2) (4 x^{2} + 5 x + 3) : 8 x^{4} - 2 x^{3} - 17 x^{2} - 19 x - 6

= \pm (8 x^{4} - 2 x^{3} - 17 x^{2} - 19 x - 6)

Expand

\pm (8 x^{4} - 2 x^{3} - 17 x^{2} - 19 x - 6) : 8 \pm x^{4} - 2 \pm x^{3} - 17 \pm x^{2} - 19 \pm x - 6 \pm

= 8 \pm x^{4} - 2 \pm x^{3} - 17 \pm x^{2} - 19 \pm x - 6 \pm

(t + 2)^{2} e^{t}

3 ((2, 0, - 1) - 2 (1, 2, 3))

\frac{e ^{x}}{( x - 2 ) ^{2}}

e^{2} (e^{m} + 3)^{4}

\frac{( x - 5 ) ( x + 1 )}{2}

What is expand (2x^2-3x-2)\pm (4x^2+5x+3) ?
The solution to expand (2x^2-3x-2)\pm (4x^2+5x+3) is 8\pm x^4-2\pm x^3-17\pm x^2-19\pm x-6\pm