What is expand e^2(e^m+3)^4 ?

The solution to expand e^2(e^m+3)^4 is e^{2+4m}+12e^{2+3m}+54e^{2+2m}+108e^{2+m}+81e^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand e^2(e^m+3)^4

expand

e^{2} (e^{m} + 3)^{4}

e^{2 + 4 m} + 12 e^{2 + 3 m} + 54 e^{2 + 2 m} + 108 e^{2 + m} + 81 e^{2}

Solution steps

e^{2} (e^{m} + 3)^{4}

(e^{m} + 3)^{4} = e^{4 m} + 12 e^{3 m} + 54 e^{2 m} + 108 e^{m} + 81

= e^{2} (108 e^{m} + e^{4 m} + 12 e^{3 m} + 54 e^{2 m} + 81)

Distribute parentheses

= e^{2} e^{4 m} + e^{2} \cdot 12 e^{3 m} + e^{2} \cdot 54 e^{2 m} + e^{2} \cdot 108 e^{m} + e^{2} \cdot 81

= e^{2} e^{4 m} + 12 e^{2} e^{3 m} + 54 e^{2} e^{2 m} + 108 e^{2} e^{m} + 81 e^{2}

Simplify

e^{2} e^{4 m} + 12 e^{2} e^{3 m} + 54 e^{2} e^{2 m} + 108 e^{2} e^{m} + 81 e^{2} : e^{2 + 4 m} + 12 e^{2 + 3 m} + 54 e^{2 + 2 m} + 108 e^{2 + m} + 81 e^{2}

= e^{2 + 4 m} + 12 e^{2 + 3 m} + 54 e^{2 + 2 m} + 108 e^{2 + m} + 81 e^{2}

\frac{( x - 5 ) ( x + 1 )}{2}

n p \cdot (n p - p + 1)^{2}

\frac{- x + a}{( a + ab ) ( - ba + a )}

(6 x + 3 y = 1, 8) (x + y = 4)

What is expand e^2(e^m+3)^4 ?
The solution to expand e^2(e^m+3)^4 is e^{2+4m}+12e^{2+3m}+54e^{2+2m}+108e^{2+m}+81e^2