What is expand-((x+1)(x-4))/6 ?

The solution to expand-((x+1)(x-4))/6 is -(x^2)/6+x/2+2/3

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expand-((x+1)(x-4))/6

expand

- \frac{( x + 1 ) ( x - 4 )}{6}

- \frac{x ^{2}}{6} + \frac{x}{2} + \frac{2}{3}

Solution steps

- \frac{( x + 1 ) ( x - 4 )}{6}

Expand

(x + 1) (x - 4) : x^{2} - 3 x - 4

= - \frac{x ^{2} - 3 x - 4}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 3 x - 4}{6} = - (\frac{x ^{2}}{6}) - (- \frac{3 x}{6}) - (- \frac{4}{6})

= - (\frac{x ^{2}}{6}) - (- \frac{3 x}{6}) - (- \frac{4}{6})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{x ^{2}}{6} + \frac{3 x}{6} + \frac{4}{6}

Cancel

\frac{3 x}{6} : \frac{x}{2}

= - \frac{x ^{2}}{6} + \frac{x}{2} + \frac{4}{6}

Cancel

\frac{4}{6} : \frac{2}{3}

= - \frac{x ^{2}}{6} + \frac{x}{2} + \frac{2}{3}

\frac{( x + 4 ) ^{2}}{2}

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\frac{x + 3}{( x + 5 ) ^{2}}

What is expand-((x+1)(x-4))/6 ?
The solution to expand-((x+1)(x-4))/6 is -(x^2)/6+x/2+2/3