What is expand (12x^7+9x^6+4x^2+pi)(x-1) ?

The solution to expand (12x^7+9x^6+4x^2+pi)(x-1) is 12x^8-3x^7-9x^6+4x^3-4x^2+pix-pi

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expand (12x^7+9x^6+4x^2+pi)(x-1)

expand

(12 x^{7} + 9 x^{6} + 4 x^{2} + π) (x - 1)

12 x^{8} - 3 x^{7} - 9 x^{6} + 4 x^{3} - 4 x^{2} + π x - π

Solution steps

(12 x^{7} + 9 x^{6} + 4 x^{2} + π) (x - 1)

Distribute parentheses

= 12 x^{7} x + 12 x^{7} (- 1) + 9 x^{6} x + 9 x^{6} (- 1) + 4 x^{2} x + 4 x^{2} (- 1) + π x + π (- 1)

Apply minus-plus rules

+ (- a) = - a

= 12 x^{7} x - 12 \cdot 1 \cdot x^{7} + 9 x^{6} x - 9 \cdot 1 \cdot x^{6} + 4 x^{2} x - 4 \cdot 1 \cdot x^{2} + π x - 1 π

Simplify

12 x^{7} x - 12 \cdot 1 \cdot x^{7} + 9 x^{6} x - 9 \cdot 1 \cdot x^{6} + 4 x^{2} x - 4 \cdot 1 \cdot x^{2} + π x - 1 π : 12 x^{8} - 3 x^{7} - 9 x^{6} + 4 x^{3} - 4 x^{2} + π x - π

= 12 x^{8} - 3 x^{7} - 9 x^{6} + 4 x^{3} - 4 x^{2} + π x - π

\frac{x + 3}{( x + 5 ) ^{2}}

(10 + 2 - 5) x (6 d i y i d e d, (8 - 4))

x (12 x y^{2} + 3 y + 4 = 0)

Q (1, - 3)

\frac{1}{( ( x ) ( a - x ) )}

What is expand (12x^7+9x^6+4x^2+pi)(x-1) ?
The solution to expand (12x^7+9x^6+4x^2+pi)(x-1) is 12x^8-3x^7-9x^6+4x^3-4x^2+pix-pi