What is expand x(12xy^2+3y+4=0) ?

The solution to expand x(12xy^2+3y+4=0) is 12x^2y^2+3xy+4x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand x(12xy^2+3y+4=0)

expand

x (12 x y^{2} + 3 y + 4 = 0)

12 x^{2} y^{2} + 3 x y + 4 x = 0

Solution steps

x (12 x y^{2} + 3 y + 4 = 0)

= x (12 x y^{2} + 3 y + 4 \cdot 0 =)

Distribute parentheses

x \cdot 12 x y^{2} + x \cdot 3 y + x \cdot 4 = 0

12 xx y^{2} + 3 x y + 4 x = 0

Expand

12 xx y^{2} + 3 x y + 4 x : 12 x^{2} y^{2} + 3 x y + 4 x

12 x^{2} y^{2} + 3 x y + 4 x = 0

Q (1, - 3)

\frac{1}{( ( x ) ( a - x ) )}

A (- 1, 2) B (2, - 1)

\frac{2 k - 1}{2 k ( 2 k + 1 ) ( 2 k + 2 )}

(π - 4)^{2}

What is expand x(12xy^2+3y+4=0) ?
The solution to expand x(12xy^2+3y+4=0) is 12x^2y^2+3xy+4x=0