What are the solutions to the equation 8pi-3pir^2=0 ?

The solutions to the equation 8pi-3pir^2=0 are r=(2sqrt(2))/(sqrt(3)),r=-(2sqrt(2))/(sqrt(3))

Find the zeros of 8pi-3pir^2=0

The zeros of 8pi-3pir^2=0 are r=(2sqrt(2))/(sqrt(3)),r=-(2sqrt(2))/(sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 π - 3 π r^{2} = 0

r = \frac{2 2}{3}, r = - \frac{2 2}{3}

Solution steps

8 π - 3 π r^{2} = 0

Move

8 π

to the right side

- 3 π r^{2} = - 8 π

Divide both sides by

- 3 π

r^{2} = \frac{8}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{8}{3}, r = - \frac{8}{3}

\frac{8}{3} = \frac{2 2}{3}

- \frac{8}{3} = - \frac{2 2}{3}

r = \frac{2 2}{3}, r = - \frac{2 2}{3}

9 x^{2} - 6 x \leq - 9

0 = s^{2} + 2 s + 2

\frac{x}{6} + 12 = (- 12)

369

8 y^{2} - 200 z^{2}

What are the solutions to the equation 8pi-3pir^2=0 ?
The solutions to the equation 8pi-3pir^2=0 are r=(2sqrt(2))/(sqrt(3)),r=-(2sqrt(2))/(sqrt(3))
Find the zeros of 8pi-3pir^2=0
The zeros of 8pi-3pir^2=0 are r=(2sqrt(2))/(sqrt(3)),r=-(2sqrt(2))/(sqrt(3))