What is expand ((x^4+1)^2)/(x^4) ?

The solution to expand ((x^4+1)^2)/(x^4) is x^4+2+1/(x^4)

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expand ((x^4+1)^2)/(x^4)

expand

\frac{( x ^{4} + 1 ) ^{2}}{x ^{4}}

x^{4} + 2 + \frac{1}{x ^{4}}

Solution steps

\frac{( x ^{4} + 1 ) ^{2}}{x ^{4}}

(x^{4} + 1)^{2} = x^{8} + 2 x^{4} + 1

= \frac{x ^{8} + 2 x ^{4} + 1}{x ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{8} + 2 x ^{4} + 1}{x ^{4}} = \frac{x ^{8}}{x ^{4}} + \frac{2 x ^{4}}{x ^{4}} + \frac{1}{x ^{4}}

= \frac{x ^{8}}{x ^{4}} + \frac{2 x ^{4}}{x ^{4}} + \frac{1}{x ^{4}}

Cancel

\frac{x ^{8}}{x ^{4}} : x^{4}

= x^{4} + \frac{2 x ^{4}}{x ^{4}} + \frac{1}{x ^{4}}

Cancel

\frac{2 x ^{4}}{x ^{4}} : 2

= x^{4} + 2 + \frac{1}{x ^{4}}

\frac{( - 3 x + 12 )}{x ( x - 3 )}

(3 x^{2} + 2 x y + 3 y^{2}) d x

\frac{( b s + a ) ^{2}}{s ^{3}}

e^{x^{2}} (\frac{d y}{d x} + 2 x y)

1 6^{(\frac{1}{2})}

What is expand ((x^4+1)^2)/(x^4) ?
The solution to expand ((x^4+1)^2)/(x^4) is x^4+2+1/(x^4)