What is expand ((x+1)(2y+1))/8 ?

The solution to expand ((x+1)(2y+1))/8 is (xy)/4+x/8+y/4+1/8

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expand ((x+1)(2y+1))/8

expand

\frac{( x + 1 ) ( 2 y + 1 )}{8}

\frac{x y}{4} + \frac{x}{8} + \frac{y}{4} + \frac{1}{8}

Solution steps

\frac{( x + 1 ) ( 2 y + 1 )}{8}

Expand

(x + 1) (2 y + 1) : 2 x y + x + 2 y + 1

= \frac{2 x y + x + 2 y + 1}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x y + x + 2 y + 1}{8} = \frac{2 x y}{8} + \frac{x}{8} + \frac{2 y}{8} + \frac{1}{8}

= \frac{2 x y}{8} + \frac{x}{8} + \frac{2 y}{8} + \frac{1}{8}

Cancel

\frac{2 x y}{8} : \frac{x y}{4}

= \frac{x y}{4} + \frac{x}{8} + \frac{2 y}{8} + \frac{1}{8}

Cancel

\frac{2 y}{8} : \frac{y}{4}

= \frac{x y}{4} + \frac{x}{8} + \frac{y}{4} + \frac{1}{8}

\frac{x + 3}{( x - 6 ) ^{3}}

(2 x^{3} + 2) (2 x^{3} - 5)^{'}

\frac{4 x + 14}{( x + 5 ) ( x - 1 )}

(a + b c) + (d e + f) (a + b)

x - 3 (x^{2} (x^{3} + 8))

What is expand ((x+1)(2y+1))/8 ?
The solution to expand ((x+1)(2y+1))/8 is (xy)/4+x/8+y/4+1/8