What is expand ((y-2)(x+1))/((y+3)(x+2)) ?

The solution to expand ((y-2)(x+1))/((y+3)(x+2)) is (yx+y-2x-2)/(yx+2y+3x+6)

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expand ((y-2)(x+1))/((y+3)(x+2))

expand

\frac{( y - 2 ) ( x + 1 )}{( y + 3 ) ( x + 2 )}

\frac{y x + y - 2 x - 2}{y x + 2 y + 3 x + 6}

Solution steps

\frac{( y - 2 ) ( x + 1 )}{( y + 3 ) ( x + 2 )}

Expand

(y + 3) (x + 2) : y x + 2 y + 3 x + 6

= \frac{( y - 2 ) ( x + 1 )}{y x + 2 y + 3 x + 6}

Expand

(y - 2) (x + 1) : y x + y - 2 x - 2

= \frac{y x + y - 2 x - 2}{y x + 2 y + 3 x + 6}

so l v e (- 2 - 5 x + x^{2} = 0)

\frac{( e ^{2 x} + 6 ) ^{6}}{12}

\frac{3 x + 1}{( x + 2 ) ( x - 1 ) ^{2}}

2 (2 x y + 4 y - 3) d x

What is expand ((y-2)(x+1))/((y+3)(x+2)) ?
The solution to expand ((y-2)(x+1))/((y+3)(x+2)) is (yx+y-2x-2)/(yx+2y+3x+6)