What is expand (3x+1)/((x+2)(x-1)^2) ?

The solution to expand (3x+1)/((x+2)(x-1)^2) is (3x+1)/(x^3-3x+2)

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expand (3x+1)/((x+2)(x-1)^2)

expand

\frac{3 x + 1}{( x + 2 ) ( x - 1 ) ^{2}}

\frac{3 x + 1}{x ^{3} - 3 x + 2}

Solution steps

\frac{3 x + 1}{( x + 2 ) ( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{3 x + 1}{( x + 2 ) ( x ^{2} - 2 x + 1 )}

Expand

(x + 2) (x^{2} - 2 x + 1) : x^{3} - 3 x + 2

= \frac{3 x + 1}{x ^{3} - 3 x + 2}

2 (2 x y + 4 y - 3) d x

e^{π ((1 - x) - k)}

y d x + (2 x - y) d y

(4 t^{2} - t - 3 = 0 - 7 + 7 i) (- 2 + 5 i)

What is expand (3x+1)/((x+2)(x-1)^2) ?
The solution to expand (3x+1)/((x+2)(x-1)^2) is (3x+1)/(x^3-3x+2)