What is expand x+y(x,z)(x+z'(x)) ?

The solution to expand x+y(x,z)(x+z'(x)) is x+xy(,xz)+y(,xz)z'

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expand x+y(x,z)(x+z'(x))

expand

x + y (x, z) (x + z^{'})

x + x y (, x z) + y (, x z) z'

Solution steps

x + y (x, z) (x + z^{'})

= x + y (, x z) (x + z^{^{'}})

Expand

y (x, z) (x + z^{'}) : x y (, x z) + y (, x z) z^{'}

= x + x y (, x z) + y (, x z) z^{'}

\frac{x ^{2} - 2}{x ^{6} - 8}

x^{4} + 4 x + 9 (x^{3} + 1) d x

(2 + π)^{2}

(X - 1) (e^{X} - e)

\frac{3 e ^{- 3 s}}{s ( s ^{2} + 1 )}

What is expand x+y(x,z)(x+z'(x)) ?
The solution to expand x+y(x,z)(x+z'(x)) is x+xy(,xz)+y(,xz)z'