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Popular >

expand e^{2(nln(n)-n)}

Solution

expand

e^{2 (n l n (n) - n)}

Solution

e^{- 2 n} n^{2 n}

Solution steps

e^{2 (n l n (n) - n)}

Expand

2 (n ln (n) - n) : 2 n ln (n) - 2 n

= e^{2 n l n (n) - 2 n}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

= e^{2 n l n (n)} e^{- 2 n}

Simplify

e^{2 n l n (n)} : n^{2 n}

= n^{2 n} e^{- 2 n}

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Frequently Asked Questions (FAQ)

What is expand e^{2(nln(n)-n)} ?
The solution to expand e^{2(nln(n)-n)} is e^{-2n}n^{2n}