What is expand 2(x^2-x-2)^2 ?

The solution to expand 2(x^2-x-2)^2 is 2x^4-4x^3-6x^2+8x+8

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expand 2(x^2-x-2)^2

expand

2 (x^{2} - x - 2)^{2}

2 x^{4} - 4 x^{3} - 6 x^{2} + 8 x + 8

Solution steps

2 (x^{2} - x - 2)^{2}

(x^{2} - x - 2)^{2} = x^{4} - 2 x^{3} - 3 x^{2} + 4 x + 4

= 2 (x^{4} - 2 x^{3} - 3 x^{2} + 4 x + 4)

Distribute parentheses

= 2 x^{4} + 2 (- 2 x^{3}) + 2 (- 3 x^{2}) + 2 \cdot 4 x + 2 \cdot 4

Apply minus-plus rules

+ (- a) = - a

= 2 x^{4} - 2 \cdot 2 x^{3} - 2 \cdot 3 x^{2} + 2 \cdot 4 x + 2 \cdot 4

Simplify

2 x^{4} - 2 \cdot 2 x^{3} - 2 \cdot 3 x^{2} + 2 \cdot 4 x + 2 \cdot 4 : 2 x^{4} - 4 x^{3} - 6 x^{2} + 8 x + 8

= 2 x^{4} - 4 x^{3} - 6 x^{2} + 8 x + 8

2 x^{2} (x + 3) se

f (x) = - \frac{64 x ( x + 2 )}{( x - 2 ) ^{5}}

22 y^{2} ln (c (4 + x))

(4 + t) d t

3 (3 x^{2} + 2 x - 4)^{2}

What is expand 2(x^2-x-2)^2 ?
The solution to expand 2(x^2-x-2)^2 is 2x^4-4x^3-6x^2+8x+8