What is expand 3(3x^2+2x-4)^2 ?

The solution to expand 3(3x^2+2x-4)^2 is 27x^4+36x^3-60x^2-48x+48

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expand 3(3x^2+2x-4)^2

expand

3 (3 x^{2} + 2 x - 4)^{2}

27 x^{4} + 36 x^{3} - 60 x^{2} - 48 x + 48

Solution steps

3 (3 x^{2} + 2 x - 4)^{2}

(3 x^{2} + 2 x - 4)^{2} = 9 x^{4} + 12 x^{3} - 20 x^{2} - 16 x + 16

= 3 (9 x^{4} + 12 x^{3} - 20 x^{2} - 16 x + 16)

Distribute parentheses

= 3 \cdot 9 x^{4} + 3 \cdot 12 x^{3} + 3 (- 20 x^{2}) + 3 (- 16 x) + 3 \cdot 16

Apply minus-plus rules

+ (- a) = - a

= 3 \cdot 9 x^{4} + 3 \cdot 12 x^{3} - 3 \cdot 20 x^{2} - 3 \cdot 16 x + 3 \cdot 16

Simplify

3 \cdot 9 x^{4} + 3 \cdot 12 x^{3} - 3 \cdot 20 x^{2} - 3 \cdot 16 x + 3 \cdot 16 : 27 x^{4} + 36 x^{3} - 60 x^{2} - 48 x + 48

= 27 x^{4} + 36 x^{3} - 60 x^{2} - 48 x + 48

- (6 x - (4 x + 8) = 9 + (6 x + 3))

(t - 4 π) (0, 4, 8 π)

\frac{( x + 1 ) ( n ^{2} - 1 )}{2 x - 7}

\frac{- 10 h - h ^{2}}{25 ( 5 + h ) ^{2}}

3 (4 - π) u^{2}

What is expand 3(3x^2+2x-4)^2 ?
The solution to expand 3(3x^2+2x-4)^2 is 27x^4+36x^3-60x^2-48x+48