What is expand (4x^2+2x-1)(2x-1)! ?

The solution to expand (4x^2+2x-1)(2x-1)! is 4x^2(2x-1)!+2x(2x-1)!-(2x-1)!

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expand (4x^2+2x-1)(2x-1)!

expand

(4 x^{2} + 2 x - 1) (2 x - 1)!

4 x^{2} (2 x - 1)! + 2 x (2 x - 1)! - (2 x - 1)!

Solution steps

(4 x^{2} + 2 x - 1) (2 x - 1)!

= (2 x - 1)! (4 x^{2} + 2 x - 1)

Distribute parentheses

= (2 x - 1)! \cdot 4 x^{2} + (2 x - 1)! \cdot 2 x + (2 x - 1)! (- 1)

Apply minus-plus rules

+ (- a) = - a

= 4 x^{2} (2 x - 1)! + 2 x (2 x - 1)! - 1 \cdot (2 x - 1)!

Multiply:

1 \cdot (2 x - 1)! = (2 x - 1)!

= 4 x^{2} (2 x - 1)! + 2 x (2 x - 1)! - (2 x - 1)!

\frac{s + 34}{( s + 5 + 3 j ) ( s + 5 - 3 j )}

(4 - x^{2 \circ} x - 2) (x)

(2.5569300000000 \dots + 1.0195000000000 \dots ln (x))^{2}

(10 x + 7 y + 3 z = 7,) (10 x + 7 x + 3 x = 10)

\frac{( 1 + j ) ^{9}}{( 1 - j ) ^{7}}

What is expand (4x^2+2x-1)(2x-1)! ?
The solution to expand (4x^2+2x-1)(2x-1)! is 4x^2(2x-1)!+2x(2x-1)!-(2x-1)!