What is expand-((1-u)^2)/2 ?

The solution to expand-((1-u)^2)/2 is -(u^2)/2+u-1/2

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expand-((1-u)^2)/2

expand

- \frac{( 1 - u ) ^{2}}{2}

- \frac{u ^{2}}{2} + u - \frac{1}{2}

Solution steps

- \frac{( 1 - u ) ^{2}}{2}

(1 - u)^{2} = 1 - 2 u + u^{2}

= - \frac{u ^{2} - 2 u + 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 2 u + u ^{2}}{2} = - (\frac{1}{2}) - (- \frac{2 u}{2}) - (\frac{u ^{2}}{2})

= - (\frac{1}{2}) - (- \frac{2 u}{2}) - (\frac{u ^{2}}{2})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{1}{2} + \frac{2 u}{2} - \frac{u ^{2}}{2}

Divide the numbers:

\frac{2}{2} = 1

= - \frac{1}{2} + u - \frac{u ^{2}}{2}

Rewrite in standard form

= - \frac{u ^{2}}{2} + u - \frac{1}{2}

e^{θ x} + e^{- y (θ - 1)}

\frac{1}{( t + c ) ^{2}}

\frac{x ( x ^{2} + 3 x - 6 )}{3}

x - 2 (x + 1) d x

A (4, - 2) B (- 3, - 1)

What is expand-((1-u)^2)/2 ?
The solution to expand-((1-u)^2)/2 is -(u^2)/2+u-1/2