What is expand ((3x-1)(x+1))/(x(x-4)) ?

The solution to expand ((3x-1)(x+1))/(x(x-4)) is (3x^2+2x-1)/(x^2-4x)

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expand ((3x-1)(x+1))/(x(x-4))

expand

\frac{( 3 x - 1 ) ( x + 1 )}{x ( x - 4 )}

\frac{3 x ^{2} + 2 x - 1}{x ^{2} - 4 x}

Solution steps

\frac{( 3 x - 1 ) ( x + 1 )}{x ( x - 4 )}

Expand

x (x - 4) : x^{2} - 4 x

= \frac{( 3 x - 1 ) ( x + 1 )}{x ^{2} - 4 x}

Expand

(3 x - 1) (x + 1) : 3 x^{2} + 2 x - 1

= \frac{3 x ^{2} + 2 x - 1}{x ^{2} - 4 x}

- \frac{6 ( 4 161 - 21 )}{61}

\frac{11 S + 10}{10 S ( S + 10 )}

cos (3 t) sin (2 t) e^{4 t} U (t - π)

\frac{( x + 1 ) ^{2}}{49}

\frac{x + 2}{( x + 2 ) x ^{2} - 2 x + 4}

What is expand ((3x-1)(x+1))/(x(x-4)) ?
The solution to expand ((3x-1)(x+1))/(x(x-4)) is (3x^2+2x-1)/(x^2-4x)