What is expand (x+1)ln(x)(1,e) ?

The solution to expand (x+1)ln(x)(1,e) is (1e,)xln(x)+1*(1e,)ln(x)

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expand (x+1)ln(x)(1,e)

expand

(x + 1) ln (x) (1, e)

(1 e,) x ln (x) + 1 \cdot (1 e,) ln (x)

Solution steps

(x + 1) ln (x) (1, e)

= (1 e,) ln (x) (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = ln (x) (1, e), b = x, c = 1

= ln (x) (1, e) x + ln (x) (1, e) \cdot 1

= (1 e,) x ln (x) + 1 \cdot (1 e,) ln (x)

\frac{x ^{2} - x + 1}{x ( x + 2 )}

\frac{7 x - 3}{4 x ( 4 x - 7 )}

\frac{1 + k ( s + 11 )}{s ( s + 3 ) ( s + 5 )}

\frac{d}{d y} ((x (y)) (y^{2} + y))

[2 + 2] (2 + 1)^{k}

What is expand (x+1)ln(x)(1,e) ?
The solution to expand (x+1)ln(x)(1,e) is (1e,)xln(x)+1*(1e,)ln(x)